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Phenol dimerises in henzene having van’t Hoff factor 0.54. What is the degree of association? (a) 0.46 (b) 92 (c) 46 (d) 0.92 |
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Answer» (d) 0.92 \(\alpha=\frac{(1-i)n}{(n-1)}=\frac{(1-0.54)2}{(2-1)}\) = 0.46 x 2 = 0.92 |
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