1.

Photoelectric emission is observed from a surface for frequencies `v_1` and `v_2` of the incident radiation `(v_1 gt v_2)`. If the maximum kinetic energies of the photoelectrons in two cases are in ratio `1 : K` then the threshold frequency `v_0` is given by.A. `(v_2 - v_1)/(K - 1)`B. `(Kv_1 - v_2)/(K - 1)`C. `(K v_2 - v_1)/(K - 1)`D. `(v_2 - v_1)/(K)`

Answer» Correct Answer - B
(b) `KE_1 = hv_1 - hv_0`
`KE_2 = hv_2 - hv_0`
`As = (KE_1)/(KE_2) = (1)/(K)`
`(h v_1 - hv_0)/( h v_2 - hv_0) = (1)/(K)`
`(K v_1 - v_2) = v_0 (K - 1)`
`v_0 = (K v_1 - v_2)/(K - 1)`.


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