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Photoelectric emission is observed from a surface for frequencies `v_(1) "and" v_(2)` of the incident radiation `(v_(1) gt v_(2))` . If maximum kinetic energies of the photo electrons in the two cases are in the ratio `1:K` , then the threshold frequency is given by:A. `(v_(2)-v_(1))/(K-1)`B. `(Kv_(1)-v_(2))/(K-1)`C. `(Kv_(2)-v_(2))/(K-1)`D. `(v_(2)-v_(2))/(K)` |
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Answer» Correct Answer - B `hv_(1) = hv_(0) +1 rArr h[v_(1) -v_(0)] = 1` ..........(1) `hv_(2) = hv_(0) +k rArr h[v_(2)-v_(0)] = k` .........(2) `((1))/((2)) =(1)/(K) = (v_(1)-v_(0))/(v_(2)-v_(0))` `v_(2) - v_(0) = Kv_(1) - Kv_(0), Kv_(0) - v_(0) = Kv_(1) - v_(2)` `v_(0) [K-1] = Kv_(1) - v_(2) v_(0) = (Kv_(1)-v_(2))/(K-1)` |
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