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Plutonium decays with a half-life of `24000` years. If the plutonium is stored for `72000` years, then the fraction of plutonium that remains is. |
Answer» `T_(1//2)=24,000 "years"` Duration of time `(t)-= 72,000 "years"` Number of half lifes `(n)=(t)/(T_(1//2))=(72000)/(24000)=3` `:. 1g overset(1)rarr(1)/(2)g overset(2)rarr(1)/(4)goverset(3)rarr(1)/(g)g` `:.` Fraction of plutonium remains `=(1)/(8) g` |
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