InterviewSolution
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InterviewSolution
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परिगणना कीजिए `:lim_(xto0)((1-cos 4x)/(1-cos5x))` |
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Answer» प्रश्नानुसार,`lim_(xto0)((1-cos4x)/(1-cos 5x))=lim_(xto0)(2sin^(2)2x)/(2sin^(2)((5x)/(2)))=lim_(xto0)(sin^(2)2x)/(sin^(2)((5x)/(2)))` `=lim_(xto0){(((sin2x)/(2x))^(2)*4x^(2))/({(sin((5x)/(2)))/((5x)/(2))}^(2)*(25x^(2))/(4))}=16/25{(lim_(2xto0)((sin2x)/(2x))^(2))/(lim_(5xto0)[(sin((5x)/(2)))/((5x)/(2))]^(2))}` `16/25xx(1^(2))/(1^(2))=16/25` |
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