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Principle of heat exchange: |
Answer» Solution :Suppose TWO objects A and B at different TEMPERATURE `T_(1)` and `T_(2)` respectively are enclosed in a box of heat resistant material as shown in figure.  Let `m_(1) `= MASS of A, `m_(2)` = mass of B,`c_(1) = ` specific heat capacity of A, `c_(2)=` specific heat capacity of B and T = common temperatureattained by A and B after the heat exchange between A and B. Here,no heatleaves the box or enters the box from outside. Hence, if` T_(1) GT T_(2)`, heat energy lost by `A( Q_(1))` = heat energy gained by `B(Q_(2))`. `:. m_(1)c_(1)(T_(1)-T) = m_(2)c_(2)(T-T_(2))` |
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