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Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solution molecules ae added to get homogeneous solution. These are called colligative properties. Application colligative properties are very useful in day-to-day life. One of its example is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles A solution `M` is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is `0.9` Given: Freezing point depression of water `(K_(f)^("water"))=1.86K kg "mol"^(-1)` Freezing point depression constant of ethanol `(K_(f)^("ethanol")=2.0K kg "mol"^(-1)` Boiling point elevation constant of water `(K_(b)^("water")=0.52K kg "mol"^(-1)` Boiling point elevation constant of ethanol `(K_(b)^("ethanol")=1.2K kg "mol"^(-1)` Standard freezing point of water`=273K` Standard freezing point of ethanol`=155.7K` Standard boiling point of water `=373K` Stadndard boiling point of ethanol `=351.5K` Vapour pressure of pure water `=32.8mm Hg ` Vapour pressure of pure ethanol`=40mm Hg` Molecular weight of water `=18 g "mol"^(-1)` Molecular weight of ethanol `=46g "mol"^(-1)` In aswering the following questions, consider the solution to be ideal dilute solutions and solutes to be non volatile and non-dissociative. The freezing point (in `.^(@)C`) of a solution containing `0.1g` of `K_(3)[Fe(CN)_(6)]` (Mol. Wt. `329`) in `100g` of water `(K_(f)=1.86K kg "mol"^(-1)` is :A. `-2.3xx10^(-2)`B. `-5.7xx10^(-5)`C. `-5.7xx10^(-3)`D. `-1.2xx10^(-2)`

Answer» Correct Answer - A
`DeltaT_(f)=ixxK_(f)xxm`
`=4xx1.86xx(0.1)/(329xx0.1)=2.3xx10^(-2)`
`rArrT_(f)=0-2.3xx10^(-2)=-2.3xx10^(-2)^(@)C`.


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