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Prove that `3sin``pi/6``sec``pi/3``-4sin``(5pi)/6``cot``pi/4``=1`

Answer» `L.H.S = 3sin(pi/6)sec(pi/3)-4sin(5pi/6)cot(pi/4)`
`=3(1/2)(2)-4sin(pi-(pi/6))(1)`
As we know, `sin(pi -x) = sinx`
Our equation becomes,
`=3(1/2)(2)-4sin(pi/6)(1)`
`=3-4(1/2) = 1 = R.H.S.`


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