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Prove that `6^(1//2)xx6^(1//4)xx6^(1//8)oo=6.` |
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Answer» We observe here that `(1/2+1/4+1/8+...oo)` is an infinite geometric series in which `a=1/2` and `r=(1/4xx2/1)=1/2` such that `|r| lt 1`. So, this sum is given by `S=((1/2))/((1-1/2))=((1/2))/((1/2))=1` ...(i) `:. 6^(1/2).6^(1/4).6^(1/8)...oo=6^((1/2+1/4+1/8+...oo))=6^(1)=6` [using (i)]. Hence, `6^(1/2).6^(1/4).6^(1/8)...oo=6`. |
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