1.

Prove that:`("cos"(2pi+theta)"c o s e c"(2pi+theta)"tan"(pi//2+theta))/("sec"(pi//2+theta)costheta"cot"(pi+theta))=1`

Answer» `L.H.S. = (cos(2pi+theta)cosec(2pi+theta)tan(pi/2+theta))/(sec(pi/2+theta)costhetacot(pi+theta))`
`= (cos(theta)cosec(theta)(-cottheta))/((-cosectheta)costhetacot(theta))`
`= (-costhetacosecthetacottheta)/(-costhetacosecthetacottheta)`
`=1 = R.H.S.`


Discussion

No Comment Found