1.

Prove that`(cos(90^0+theta)sec(-theta)"tan"(180^0-theta))/(sec(360^0-theta)sin(180^0+theta)cot(90^0-theta))=-1`

Answer» `L.H.S.=(cos(90^@+theta)sec(-theta)tan(180^@-theta))/(sec(360^@-theta)sin(180^@+theta)cot(90^@-theta))`
`=((-sintheta)(sectheta)(-tantheta))/((sectheta)(-sintheta)(tantheta))=-1=R.H.S.`


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