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Prove that \(f(x) = \begin{cases} sin\frac {1}{x}, & \quad \text{when x≠0;} \text{}\\ 0, & \quad \text{when x=0} \end{cases}\) is discontinuous at x=0 |
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Answer» \(\lim\limits_{x \to0} \) sin\(\frac{1}{x}\) = 0 sin\(\frac{1}{x}\) is bounded function between -1 and +1. Also, f(0)=0 Since, \(\lim\limits_{x \to0} \) f(x) = f(0) Hence, f is a continuous function. |
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