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Prove that: log10 tan 1°. log10 tan 2°……. log10 tan 89° = 0 |
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Answer» L.H.S. = log10 tan 1°. log10 tan 2°…. log10 tan 45° log10 tan 89° = log10 tan 1°. log10 tan 2°…. log10 (1)…. log10 tan 89° = log10tan 1°- log10 tan 2°…. x 0 x…. log10 tan 89° = 0 = R.H.S. Hence Proved. |
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