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Prove that: log10 tan 1°. log10 tan 2°……. log10 tan 89° = 0

Answer»

L.H.S.

= log10 tan 1°. log10 tan 2°…. log10 tan 45° log10 tan 89°

= log10 tan 1°. log10 tan 2°…. log10 (1)…. log10 tan 89°

= log10tan 1°- log10 tan 2°…. x 0 x…. log10 tan 89°

= 0

= R.H.S. Hence Proved.



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