InterviewSolution
Saved Bookmarks
| 1. |
Prove that: `(sin(A-C)+2sinA+sin(A+C)) / ("sin"("B"-"C")+2sinB+"sin"(B+C))`=`(sinA)/(sinB)`` |
|
Answer» `L.H.S. = (sin(A-C)+2sinA+sin(A+C)) / (sin(B-C)+2sinB+sin(B+C))` `=(sinAcosC-cosAsinC+2sinA+sinAcosC+cosAsinC)/(sinBcosC-cosBsinC+2sinB+sinBcosC+cosBsinC)` `=(2sinA(1+cosC))/(2sinB(1+cosC))` `=sinA/sinB = R.H.S.` |
|