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Prove that `(sin(x+y))/(sin(x-y))=(tanx+tany)/(tanx-tany)` |
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Answer» `L.H.S. = (sin(x+y))/(sin(x-y))` `=(sinxcosy+sinycosx)/(sinxcosy-cosxsiny)` Dividing numerator and denominator by `cosxcosy` `=((sinx/cosx)+(siny/cosy))/((sinx/cosx)-(siny/cosy))` `=(tanx+tany)/(tanx-tany)=R.H.S` |
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