InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Pythagorus theorm solved |
|
Answer» Tnkx In a right triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides.We are given a triangle ABC right angled at BWe need to prove that AC^2=AB^2+BC^2Let us draw BD perpendicular AC∆ABC~∆ADC. (Theorem)AD\\AB=AB\\AC. (Sides are proportional)AD.AC=AB^2. (1)Also, ∆BDC~∆ABCCD\\BC=BC\\ACCD.AC.=BC^2. (2)Adding (1)&(2),AD.AC+CD.AC=AB^2+BC^2or, AC(AD+CD)=AB^2+BC^2or, AC.AC=AB^2+BC^2or, AC^2=AB^2+BC^2Thank U By ARMAN INAMDAR |
|