1.

Quantity 2: If A is twice as efficient as B and they both can do a piece of work in 12 days, then what percentage of the work will B do alone in 20 days?1). Quantity 1 > Quantity 22). Quantity 1 < Quantity 23). Quantity 1 ≥ Quantity 24). Quantity 1 ≤ Quantity 2

Answer»

Solving for QUANTITY 1:

A’s 1 day WORK = 1/15

B’s 1 day work = ½ × 1/15 = 1/30

(A + B) ’s 1 day work = 1/15 + 1/30 = 1/10

In 8 days, work done = 8/10

⇒ Quantity 1 = (8/10) × 100 = 80%

Solving for Quantity 2:

Let B’s 1 day work = 1/x

A’s 1 day work = 2/x

(A + B) ’s 1 day work = 1/x + 2/x = 3/x

⇒ 3/x = 12

⇒ x = 36

Hence, B’s 1 day work = 1/36

In 20 days, work done by B = 20 × 1/36 = 5/9

⇒ Quantity 2 = (5/9) × 100 = 55.55%

∴ Quantity 1 > Quantity 2


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