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Quantity 2: If A is twice as efficient as B and they both can do a piece of work in 12 days, then what percentage of the work will B do alone in 20 days?1). Quantity 1 > Quantity 22). Quantity 1 < Quantity 23). Quantity 1 ≥ Quantity 24). Quantity 1 ≤ Quantity 2 |
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Answer» Solving for QUANTITY 1: A’s 1 day WORK = 1/15 B’s 1 day work = ½ × 1/15 = 1/30 (A + B) ’s 1 day work = 1/15 + 1/30 = 1/10 In 8 days, work done = 8/10 ⇒ Quantity 1 = (8/10) × 100 = 80% Solving for Quantity 2: Let B’s 1 day work = 1/x A’s 1 day work = 2/x (A + B) ’s 1 day work = 1/x + 2/x = 3/x ⇒ 3/x = 12 ⇒ x = 36 Hence, B’s 1 day work = 1/36 In 20 days, work done by B = 20 × 1/36 = 5/9 ⇒ Quantity 2 = (5/9) × 100 = 55.55% ∴ Quantity 1 > Quantity 2 |
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