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Question : Compute the heat generated which transferring 96000 coulomb of charge in one hour through a potential difference 50V.

Answer»

SOLUTION :According to Joule.s law of heating the amount of heat PRODUCED is given by
`H = Vt`
where V = 50 V
I = charge/time = 9600 Coulomb/1hr = `(96000)/(60 xx 60) = 80/30 A`
and t = 1 hr = `60 xx 60 ` sec
So `H = 50 xx 80/30 xx 60 xx 60`
4800000 J
` = 4.8 xx 10^6 J`


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