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Question :The far point of a myopic person is 80cm in front of the eye. What is the nature and power of the lens required to correct the problem.

Answer»

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Solution :The PERSON is suffering from an eye defect called myopia. In this defect, the IMAGE is formed in front of the retina. Hence a concave lens is used to CORRECT this defect of vission.
OBJECT distance, u - infinity - `oo`
Image distance, v=-8cm, Focal length=f
According to the lens formula
`1/v-1/u = 1/f`
`- 1/80 - 1/oo = 1/f`
`1/f =- 1/80`
`f =- 80 cm = - 0.8 m`
We know , power , P = 1/f(in meter)
`P= (1)/(-0.8) = - 1.25D`
A concave lens of power -1.25D is required by the person to correct his defect .


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