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Radiation corresponding to the transition n=4 to n=2 in hydrogen atoms falls on a certain metal (work function=2.5 eV). The maximum kinetic energy of the photo-electrons will be:A. `0.55 eV`B. `2.55 eV`C. `4.45 eV`D. None of these |
Answer» Correct Answer - 4 `E_(n)=-13.6/n^(2) eV, E_(2)=13.6/2^(2)` `E_(4)=-13.6/4^(2)eV//atom` DeltaE=E_(4)-E_(2)=2.55 eV` Absorbed energy = work function of metal `+K.E. 2.55=2.5+K.E., K.E.=0.05 eV` |
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