1.

Radiation of `lambda`=155 nm was irradiated on Li(work function =5 eV) plante . The stopping potential (in eV) is.A. 4 eVB. 5 eVC. 3 eVD. 1 eV

Answer» Correct Answer - C
`V=(hc)/lambda_(2)-phi_(0)=3 eV`


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