InterviewSolution
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InterviewSolution
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Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are `tau = 1// lambda` and `t_(1//2) = 0.693//lambda`. Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after `n` half lives of radioactive elements can be calculated using the relation: `N = N_(0) ((1)/(2))^(n)` Select the correct relation.A. `t_(1//2) = (0.693)/(lambda)`B. `tau = (1)/(lambda)`C. `tau = 1.44 xx t_(1//2)`D. `tau = (t_(1//2))/(0.693)` |
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Answer» Correct Answer - C `tau = 1.44 xx t_(1//2)` |
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