InterviewSolution
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InterviewSolution
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Radioactivity of a radioactive element remains `1//10` of the original radioactivity after `2.303` seconds. The half life period isA. `2.303`B. `0.2303`C. `693`D. `0.693` |
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Answer» Correct Answer - D `K=(2.303)/(t)log``(a)/(a-x)` `[{:(t=2.303(given)),((a-x)=(1)/(10)a_(0)):}]` `=(2.303)/(t)log``(1)/(a//10)=1` `:. t_(1//2)=(0.693)/(K)=(0.693)/(1)=0.693` |
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