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Radioactivity of a radioactive element remains `(1)/(10)` of the original radioactivity after 2.303 seconds. The half-life period isA. 2.303B. 0.2303C. 0.693D. 0.0693 |
Answer» Correct Answer - C `2.303 = (2.303)/(0.693) xx t_(1//2) log 10` |
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