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Radon `220` decays to Bismuth `212` by the following series of decay `{:(._(86)Rnrarr_(84),Po^(216)+_(2),He^(4),,T_(1//2)=55s,),(._(84)Po^(216)rarr_(82),Pb^(212)+_(2),He^(4),,T_(1//2)=0.016s,),(._(82)Pb^(212)rarr_(83),Bi^(212)+_(-1),e^(0),,T_(1//2)=10..6s,):}` If certain mass of randon is allowed to decay in certain container, after five minutes element with greatest and least mass will respectively beA. Randon, bismuthB. Polonium, leadC. Lead, bismuthD. Bismuth, lead |
Answer» Correct Answer - C small `T_(1//2)` indicates that more such reactions take place. |
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