InterviewSolution
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InterviewSolution
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Range of `f(theta)=cos^2theta(cos^2theta+1)+2 sin^2theta` isA. `[3//4,1]`B. `[3//16,1]`C. `[3//4,7//4]`D. `[7//4,2]` |
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Answer» Correct Answer - D `f(theta)=cos^2theta(cos^2theta+1)+2sin^2theta` `=cos^4theta+cos^2theta+sin^2theta+sin^2theta` `=cos^4theta+1+1-cos^2theta` `=(cos^2theta-1/2)^2+2-1/4` `=(cos^2theta-1/2)^2+7/4` `f_("min")=7/4` `f_("max")=1/4+7/4=2` |
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