InterviewSolution
Saved Bookmarks
| 1. |
Ratio of frequency of revolution of electron in the second state of `He^(o+)` revolution of electron in the second state `He^(Theta)` and second state of hydrogen isA. `(32)/(27)`B. `(27)/(32)`C. `(1)/(34)`D. `(27)/(2)` |
|
Answer» Frequency `v = (v)/(2pi r), v prop (Z)/(n) and r prop n^(2)/(Z)` `rArr v prop (Z^(2))/(n^(2)) ` so `(He^(o+))/(n_(2)^(o+)) = (Z^(2)//3^(2))/(1^(2)//2^(3)) = (8 xx 4)/(27) = (32)/(27)` second excited `rArr n = 3` |
|