1.

Ratio of frequency of revolution of electron in the second state of `He^(o+)` revolution of electron in the second state `He^(Theta)` and second state of hydrogen isA. `(32)/(27)`B. `(27)/(32)`C. `(1)/(34)`D. `(27)/(2)`

Answer» Frequency `v = (v)/(2pi r), v prop (Z)/(n) and r prop n^(2)/(Z)`
`rArr v prop (Z^(2))/(n^(2)) `
so `(He^(o+))/(n_(2)^(o+)) = (Z^(2)//3^(2))/(1^(2)//2^(3)) = (8 xx 4)/(27) = (32)/(27)`
second excited `rArr n = 3`


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