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Rationalise the denominator 6 + √3/ √5 + √2. |
Answer» \(6 + \sqrt3\over \sqrt5 + \sqrt2\). Multiply by √5 - √2 both numerator and denominator. = \(6 + \sqrt3\over \sqrt5 + \sqrt2\) x \(\sqrt5 - \sqrt2\over\sqrt5 - \sqrt2\) = \(6\sqrt5 - 6\sqrt2 + \sqrt15 - \sqrt6 \over 5 - 2\) = \(6\sqrt5 - 6\sqrt2 + \sqrt15 - \sqrt6 \over 3\) |
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