

InterviewSolution
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Re-arrange sutably and find the sum in each of the following.(i) \(\frac{11}{12}+\frac{-17}{3}+\frac{11}{2}+\frac{-25}{2}\)(ii) \(\frac{-6}{7}+\frac{-5}{6}+\frac{-4}{9}+\frac{-15}{7}\)(iii) \(\frac{3}{5}+\frac{7}{3}+\frac{9}{5}+\frac{-13}{15}+\frac{-7}{3}\)(iv) \(\frac{4}{13}+\frac{-5}{8}+\frac{9}{5}+\frac{-8}{3}+\frac{9}{13}\)(v) \(\frac{2}{3}+\frac{-4}{5}+\frac{1}{3}+\frac{2}{5}\)(vi) \(\frac{1}{8}+\frac{5}{12}+\frac{2}{7}+\frac{7}{12}+\frac{9}{7}+\frac{-5}{16}\) |
Answer» (i) \(\frac{11}{12}-\frac{17}{3}-\frac{14}{2}\) = \(\frac{11-68-84}{12}\) = \(\frac{-141}{12}\) (ii) \(\frac{-6}{7}-\frac{-15}{7}-\frac{5}{6}-\frac{4}{9}\) = \(\frac{-21}{7}-\frac{5}{6}-\frac{4}{9}\) = \(\frac{-3\times 18-5\times 3-4\times 2}{18}\) = \(\frac{-77}{18}\) (iii) \(\frac{3}{5}+\frac{9}{5}+\frac{7}{3}-\frac{7}{3}-\frac{-13}{15}\) = \(\frac{12}{5}-\frac{13}{15}\) = \(\frac{12\times 3}{5\times 3}-\frac{13}{15}\) = \(\frac{36-13}{15}\) = \(\frac{23}{15}\) (iv) \(\frac{4}{13}+\frac{9}{13}-\frac{8}{13}-\frac{5}{8}+\frac{9}{5}\) = \(\frac{4+9-8}{13}-\frac{5}{8}+\frac{9}{5}\) = \(\frac{5}{13}-\frac{5}{8}+\frac{9}{5}\) = \(\frac{200-325+936}{520}\) = \(\frac{811}{520}\) (v) \(\frac{2}{3}+\frac{1}{3}+\frac{2}{5}-\frac{4}{5}\) = \(\frac{2+1}{3}+\frac{2-4}{5}\) = \(\frac{3}{3}-\frac{2}{5}\) = \(\frac{15-6}{15}\) = \(\frac{9}{15}\) = \(\frac{3}{5}\) (vi) \(\frac{5}{12}+\frac{7}{12}+\frac{2}{7}+\frac{9}{7}+\frac{1}{8}-\frac{5}{16}\) = \(\frac{12}{12}+\frac{11}{7}+\frac{1}{8}-\frac{5}{16}\) = \(\frac{336+528+42-105}{336}\) = \(\frac{801}{336}\) |
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