Redraw the circuit of Question 1, putting in an ammeter to measure to current through the resistors and a voltmeter to measure the potential difference across the 12 Omega resistor. What would be the readings in the ammeter and the voltmeter?

Redraw the circuit of Question 1, putting in an ammeter to measure to

1.	Redraw the circuit of Question 1, putting in an ammeter to measure to current through the resistors and a voltmeter to measure the potential difference across the 12 Omega resistor. What would be the readings in the ammeter and the voltmeter?
Answer» Solution :The redrawn circuit is shown in fig.12.2 Here AMMETER A has been joined in series of the circuit and voltmeter V is joined in parallel to `12 Omega` resistor. Here total VOLTAGE of BATTERY `V=3 times 2V=6V` Total resistance of series arrangement `R=R_1+R_2+R_3=5+8+12=25 Omega` `therefore` Ammeter READING= Current FLOWING in the circuit `I=V/R=(6V)/(25 Omega)=0.24A` `therefore` Voltmeter reading =Potential difference across `12 Omega` resistor `V.=IR_3=0.24 times 12=2.88V`