Redraw the circuit of question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure potential difference across the 12 Omega resistor. What would be the readings in the ammeter and the voltmeter?

Redraw the circuit of question 1, putting in an ammeter to measure the

1.	Redraw the circuit of question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure potential difference across the 12 Omega resistor. What would be the readings in the ammeter and the voltmeter?
Answer» Solution : `R_(s) =(5+8+12)` `=25 Omega` V= IR `I = (V)/(R) = (6)/(25) = 0.24 A ` Potential DIFFERENCE across `12 Omega` resistor is `V = IR = 0.24xx12= 2.88` V HENCE reading of AMMETER `= 0.24 A` reading of voltmeter = 2.88 V