Reduce the equation 3x – 2y + 6 = 0 to the intercept form and find t

1.	Reduce the equation 3x – 2y + 6 = 0 to the intercept form and find the x and y - intercepts.
Answer» Given: equation is 3x − 2y + 6 = 0 Concept Used: Line in intercepts form is \(\frac{x}{a}+\frac{y}{b}=1\) ( a and b are x and y intercepts resp.) Explanation: 3x − 2y = - 6 \(\frac{3}{-6}x+\frac{2y}{6}=1\) [Dividing both sides by - 6] \(\frac{x}{-2}+\frac{y}{3}=1\) Thus, the intercept form of the given line ∴ x - intercept = −2 and y - intercept = 3

Reduce the equation 3x – 2y + 6 = 0 to the intercept form and find the x and y - intercepts.

Answer»

Given: equation is 3x − 2y + 6 = 0

Concept Used:

Line in intercepts form is \(\frac{x}{a}+\frac{y}{b}=1\) ( a and b are x and y intercepts resp.)

Explanation:

3x − 2y = - 6

\(\frac{3}{-6}x+\frac{2y}{6}=1\) [Dividing both sides by - 6]

\(\frac{x}{-2}+\frac{y}{3}=1\)

Thus, the intercept form of the given line

∴ x - intercept = −2 and y - intercept = 3