Reduce the equation 6x + 2y + 5 = 1 into intercept form and find its i

1.	Reduce the equation 6x + 2y + 5 = 1 into intercept form and find its intercepts on the axes.
Answer» The given equation is 6x + 2y + 5 = 0 Here, A = 6, B = 2, C = 5 ∴ Equation in intercept form is \(\frac{x}{-\frac{C}{A}} + \frac{y}{-\frac{C}{B}}\) = 1 ⇒ \(\frac{x}{-\frac{5}{6}} + \frac{y}{-\frac{2}{6}}\) = 1 ⇒ \(\frac{x}{-\frac{5}{6}} + \frac{y}{-\frac{2}{6}}\) = 1, ⇒ \(\frac{x}{-\frac{5}{6}} + \frac{y}{-\frac{1}{3}}\) = 1, where a (intercept on x-axis) = − \(\frac{5}{6}\) and b (intercept on y – axis) = − \(\frac{1}{3}\)

Reduce the equation 6x + 2y + 5 = 1 into intercept form and find its intercepts on the axes.

Answer»

The given equation is

6x + 2y + 5 = 0

Here, A = 6, B = 2, C = 5

∴ Equation in intercept form is

\(\frac{x}{-\frac{C}{A}} + \frac{y}{-\frac{C}{B}}\) = 1

⇒ \(\frac{x}{-\frac{5}{6}} + \frac{y}{-\frac{2}{6}}\) = 1

⇒ \(\frac{x}{-\frac{5}{6}} + \frac{y}{-\frac{2}{6}}\) = 1,

⇒ \(\frac{x}{-\frac{5}{6}} + \frac{y}{-\frac{1}{3}}\) = 1, where a (intercept on x-axis)

= − \(\frac{5}{6}\) and b (intercept on y – axis) = − \(\frac{1}{3}\)