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Resolve `(1)/(x^(2)-7x+12)` into partical fractions.A. `(1)/(x-4)-(1)/(x-3)`B. `(1)/(x-3)+(1)/(x-4)`C. `(2)/(x-4)-(1)/(x-3)`D. `(1)/(x+3)-(1)/(x+4)` |
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Answer» `(1)/(x^(2)-7x+12)=(1)/((x-3)(x-4))` Let `(1)/((x-3)(x-4))=(A)/(x-3)+(B)/(x-4)`…..`(1)` `(1)/((x-3)(x-4))=(A(x-4)+B(x-3))/((x-3)(x-4))` Consider , `A(x-4)+B(x-3)=1` Put `x=4`, we get `B=1` Put `x=3`, we get `-A=1` `implies A=-1` Substitute these value in Eq. `(1)`, we get `(1)/((x-3)(x-4))=(1)/(x-4)-(1)/(x-3)`. |
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