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Resolve `(1)/(x^(2)-(a+b)x+ab)` into partical fractions.A. `(1)/(a+b)[(1)/(x-a)+(1)/(x-b)]`B. `(1)/(a+b)[(1)/(x-a)-(1)/(x-b)]`C. `(1)/(a-b)[(1)/(x-a)+(1)/(x-b)]`D. `(1)/(a-b)[(1)/(x-a)-(1)/(x-b)]`

Answer» `(1)/(x^(2)-(a+b)x+ab)=(A)/(x-a)+(B)/(x-b)`.


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