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Resolve `(2x)/(3(x-1)(x-3))` into partical fractions.A. `(1)/(x+3)-(1)/(3(x+1))`B. `(1)/(x-3)-(1)/(x+1)`C. `(1)/(x-3)-(1)/(3(x+1))`D. `(1)/(x-3)-(2)/(3(x-1))` |
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Answer» Let `((2x)/(3))/((x-1)(x-3))=(A)/((x-1))+(B)/((x-3))` `((2x)/(3))/((x-1)(x-3))=(A(x-3)+B(x-1))/((x-1)(x-3))` Consider , `A(x-3)+B(x-1)=(2x)/(3)` Put `x=3`, `2B=2impliesB=1`. Put `x=1`, `-2A=(2)/(3)impliesA=-(1)/(3)` `:. (2x)/(3(x-1)(x-3))=(1)/(x-3)-(1)/(3(x-1))` |
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