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Resolve `(5)/((x+2)(x+3))` into partical fractions.A. `5((1)/(x+2)+(1)/(x+3))`B. `5((1)/(x+2)-(1)/(x+3))`C. `10((1)/(x+2)-(1)/(x+3))`D. `10((1)/(x+2)+(1)/(x+3))` |
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Answer» Let `(5)/((x+2)(x+3))=(A)/((x+2))+(B)/((x+3))` `(5)/((x+2)(x+3))=(A(x+3)+B(x+2))/((x+2)(x+3))` Consider `A(x+3)+B(x+2)=5` If `x=-3`, `-B=5impliesB=-5` If `x=-2`, `A=5`. `:.(5)/((x+2)(x+3))=(5)/(x+2)-(5)/(x+3)`. |
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