1.

Rolle's Theorem is applicable in the interval [-5, 5] for the function1. \(\rm f (x) = x^4\)2. \(\rm f (x) = 5x^4\)3. \(\rm f (x) = 2x^3 + 3\)4. \(\rm f(x) = \pi |x|\)

Answer» Correct Answer - Option 2 : \(\rm f (x) = 5x^4\)

Concept:

If real valued function f (x)

(i) is continuous in [a, b]

(ii) is differentiable on (a, b)

(iii) f (a) = f(b)

Then there exists at least one real value c in the interval (a, b) such that f'(c) = 0

Calculation:

If we take\(\rm f (x) = 5x^4\)

(i) f (x) is continuous in (-5, 5)

(ii) f (x) is differentiable in (-5, 5)

(iii) f (-5) = f (5)

So,\(\rm f (x) = 5x^4\)satisfies all the conditions of Rolle's Theorem, therefore a point c, such that f (c') = 0

20\(\rm c^3\)= 0 = c = 0\(\rm \epsilon \)(-5, 5)

Hence Option 2 is correct.



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