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साबित करे की `3(sin theta - cos theta)^(4)+4(sin^(6)theta + cos^(6)theta )+6(sin theta + cos theta)^(2)=13`

Answer» बायाँ पक्ष `=3(sin theta - cos theta)^(4)+4(sin^(6) theta + cos^(6) theta)+6(sin theta + cos theta)^(2)`
`=3{(sin theta - cos theta)^(2)+4{(sin^(2) theta)^(3)+(cos^(2) theta)^(3)+6(sin^(2)theta + cos^(2) theta + 2 sin theta . cos theta)`
`=3(1+4 sin^(2)theta. cos^(2) theta- 4 sin theta . cos theta) + 4 (sin^(2) theta + cos^(2)theta)^(2)`
`=3+12 sin^(2) theta . cos^(2) theta + 4 -12 sin^(2) . cos^(2) theta +6`
=13=दायाँ पक्ष


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