1.

`(secx-1)(secx+1)`

Answer» Let `y=(secx-1)(secx+1)`
`y=(sec^(2)-1) [therefore (a+b)(a-b)=a^(2)-b^(2)]`
`=tan^(2)x`
`therefore (dy)/(dx) 2tanx. d/(dx)tanx`
`=2tanx.sec^(2)x` [By chain rule]


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