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`(secx-1)(secx+1)` |
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Answer» Let `y=(secx-1)(secx+1)` `y=(sec^(2)-1) [therefore (a+b)(a-b)=a^(2)-b^(2)]` `=tan^(2)x` `therefore (dy)/(dx) 2tanx. d/(dx)tanx` `=2tanx.sec^(2)x` [By chain rule] |
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