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Show that constant function is always differentiable |
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Answer» Let a be any constant number. Then, f(x) = a f'(x) = \(\lim\limits_{h \to 0}\) \(\frac{f(x+h)-f(x)}{h}\) We know that coefficient of a linear function is a = \(\frac{y_2-y_1}{x_2-x_1}\) Since our function is constant, y1 = y2 Therefore, a = 0 Now, f'(x) = \(\lim\limits_{h \to 0}\) \(\frac{a-a}{h}\) = \(\lim\limits_{h \to 0}\) \(\frac{0}{h}\) = \(\lim\limits_{h \to 0}\) 0 = 0 Thus, the derivative of a constant function is always 0. |
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