Show that relative lowering of vapour pressure is a colligative proper

1.	Show that relative lowering of vapour pressure is a colligative property.
Answer» Consider a binary solution containing a nonvolatile solute. If P and P are vapour pressures of a pure solvent and the solution respectively then, Lowering of vapour pressure = ΔP = P₀ – P Relative lowering of vapour pressure = \(\frac{P_0-P}{P_0}\) By Raoult’s law, \(\frac{P_0-P}{P_0}\) = x₂ Where x₂ is mole fraction of the solute. Therefore the relative lowering of vapour pressure is a colligative property.

Show that relative lowering of vapour pressure is a colligative property.

Answer»

Consider a binary solution containing a nonvolatile solute. If P and P are vapour pressures of a pure solvent and the solution respectively then, Lowering of vapour pressure = ΔP = P₀ – P

Relative lowering of vapour pressure = \(\frac{P_0-P}{P_0}\)

By Raoult’s law,

\(\frac{P_0-P}{P_0}\) = x₂

Where x₂ is mole fraction of the solute. Therefore the relative lowering of vapour pressure is a colligative property.

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Show that relative lowering of vapour pressure is a colligative property.

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