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Show that the following equation represents a pair of lines.4x2 + 4xy + y2 = 0 |
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Answer» Comparing the equation 4x2 + 4xy + y2 = 0 with ax2 + 2hxy + by2 = 0, we get, a = 4, 2h = 4, i.e. h = 2 and b = 1 ∴ h2 – ab = (2)2 – 4(1) = 4 – 4 = 0 Since the equation 4x2 + 4xy + y2 = 0 is a homogeneous equation of second degree and h2 – ab = 0, the given equation represents a pair of lines which are real and coincident. |
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