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Simplify `2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)` |
Answer» `2sin^2beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)` `2sin^2beta+4cos(alpha+beta)(2sinalphasinbeta+cos(alpha+beta))` `2sin^2beta-1+2cos(alpha+beta)(2sinalphasinbeta+cosalphacosbeta)` `-cos2beta+2cos(alpha+beta)cos(alpha-beta)` `-cos2beta+cos(alpha+beta+alpha-beta)+cos(alpha+beta-alpha+beta)` `-cos2beta+2cosalpha+cos2beta` `cos2alpha`. |
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