` sin^4 theta + 2 sin^2 theta ( 1 - 1/(cosec^2 theta)) + cos^4 theta = – InterviewSolution

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1.	` sin^4 theta + 2 sin^2 theta ( 1 - 1/(cosec^2 theta)) + cos^4 theta =`
Answer» `sin^4theta+2sin^2theta(1-1/(cosec^2theta))+cos^4theta` `=sin^4theta+2sin^2theta(1-sin^2theta)+cos^4theta` `=sin^4theta+2sin^2thetacos^2theta+cos^4theta` `=(sin^2theta+cos^2theta)^2` `=1^2 = 1` So, value of the required expression is `1`.

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