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Sin²A +Cos²A +Tan²A = ? |
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Answer» Sin2A+Cos2A+Tan2A=sin2a +cos2a+sin2a /cos2a1+sin2a /cos2a Cos2a+sin2a /cos2a1/cos2aSec2a Sec square A 1+tan2A 1+sin^2A/cos^2A(Cos^2A+sin^2A)/cos^2A1/cos^2ASec^2A Solve it if you can |
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