1.

Skim milk is prepared by the removal of some of the fat from whole milk. This skim milk is found to contain 90.5% water, 3.5% protein, 5.1% carbohydrate, 0.1% fat and 0.8% ash. If the original milk contained 4.5% fat, Calculate its composition assuming that fat only was removed to make the skim milk and that there are no losses in processing.(a) Fat = 4.5%, Water = 86.5%, protein = 3.3%, carbohydrate = 4.9%, ash = 0.8%(b) Fat = 4.5%, Water = 83.5%, protein = 3.0%, carbohydrate = 4.5%, ash = 0.9%(c) Fat = 4.6%, Water = 80.5%, protein = 3.5%, carbohydrate = 4.0%, ash = 0.9%(d) Fat = 4.6%, Water = 81.5%, protein = 3.3%, carbohydrate = 4.5%, ash = 0.8%This question was addressed to me during an interview.My enquiry is from Energy Balance Numericals Without Reactions topic in chapter Energy Balance of Bioprocess Engineering

Answer»

Right choice is (a) FAT = 4.5%, Water = 86.5%, protein = 3.3%, carbohydrate = 4.9%, ASH = 0.8%

EASY explanation: Basis: 100 kg of skim milk.

This contains, therefore, 0.1kg of fat. Let the fat which was removed from it to make skim milk be x kg.

Total original fat = (x + 0.1) kg

Total original mass = (100 + x) kg

and as it is shown that the original fat content was 4.5% so,

(x+0.1)/(100+x) = 0.045

where = x+0.1 = 0.045(100+x)

x = 4.6 kg

So the COMPOSITION of the whole milk is then fat = 4.5%, water = 90.5/104.6 = 86.5%, protein = 3.5/104.6 = 3.3%, carbohydrate = 5.1/104.6 = 4.9% and ash = 0.8%.


Discussion

No Comment Found

Related InterviewSolutions