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Solve 2x^2+√2x+2= 0.(a) \(\frac{-1±i\sqrt{7}}{2\sqrt{2}}\)(b) \(\frac{1±i\sqrt{7}}{2\sqrt{2}}\)(c) \(\frac{1±\sqrt{7}}{2\sqrt{2}}\)(d) \(\frac{-1±\sqrt{7}}{2\sqrt{2}}\)I got this question during an online interview.The origin of the question is Quadratic Equations topic in section Complex Numbers and Quadratic Equations of Mathematics – Class 11 |
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Answer» RIGHT choice is (a) \(\frac{-1±i\sqrt{7}}{2\sqrt{2}}\) To explain: 2x^2+√2x+2 = 0 =>D=(\(\sqrt{2}\))^2 – 4.2.2 = 2-16 = -14. Since D ≤ 0, IMAGINARY roots are there. =>x = \(\frac{-\sqrt{2}±\sqrt{D}}{2.2} = \frac{-\sqrt{2}±i\sqrt{14}}{4} = \frac{-1±i\sqrt{7}}{2\sqrt{2}}\). |
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