Solve the following :Henry’s law constant for the solubility of meth

1.	Solve the following :Henry’s law constant for the solubility of methane in benzene is 4.27 × 10-5 mm Hg mol dm-3 at constant temperature. Calculate the solubility of methane at 760 mm Hg pressure at same temperature.
Answer» Given : Henry’s law constant = K = 4.27 × 10^-5 mm Hg mol dm^-3 Pressure of the gas = P = 760 mm Hg K_H = 4.27 × 10^-5 mm^-1 mol dm^-3 = 4.27 × 10^-5 × 760 atm^-1 mol dm^-3 = 3245 × 10^-5 atm^-1 mol dm^-3 P = 760 mm = \(\frac{760}{760}\)=1 atm By Henry’s law, S = K_Hx P = 3.245 x 10^-2atm^-1 mol dm^-3 x 1 atm = 3.245 × 10^-2 mol dm^-3 ∴ Solubility of methane = 3.245 × 10^-2 mol dm^-3

Solve the following :Henry’s law constant for the solubility of methane in benzene is 4.27 × 10-5 mm Hg mol dm-3 at constant temperature. Calculate the solubility of methane at 760 mm Hg pressure at same temperature.

Answer»

Given :

Henry’s law constant = K

= 4.27 × 10^-5 mm Hg mol dm^-3

Pressure of the gas = P = 760 mm Hg

K_H = 4.27 × 10^-5 mm^-1 mol dm^-3

= 4.27 × 10^-5 × 760 atm^-1 mol dm^-3

= 3245 × 10^-5 atm^-1 mol dm^-3

P = 760 mm = \(\frac{760}{760}\)=1 atm

By Henry’s law,

S = K_Hx P = 3.245 x 10^-2atm^-1 mol dm^-3 x 1 atm

= 3.245 × 10^-2 mol dm^-3

∴ Solubility of methane = 3.245 × 10^-2 mol dm^-3

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Solve the following :Henry’s law constant for the solubility of methane in benzene is 4.27 × 10-5 mm Hg mol dm-3 at constant temperature. Calculate the solubility of methane at 760 mm Hg pressure at same temperature.

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