1.

Solve the following :The solubility of dissolved oxygen to 27 °C is 2.6 × 10-3 mol dm-3 at 2 atm. Find its solubility at 8.4 atm and 27 °C.

Answer»

Given : 

Solubility of O2

= S1 = 2.6 × 10-3 mol dm-3

Initial pressure of O2 = P1 = 2 atm

Final pressure of O2 = P2 = 8.4 atm

Solubility of O2 = S2 = ?

(i) By Henry’s law,

S1 = KH x P1

∴ Henry’s law constant KH is,

KH\(\frac{S_1}{P_1}\) \(\frac{2.6 \times 10^{-3}}{2}\)

= 1.3 × 10-3 mol dm-3 atm-1

(ii) Now,

S2 = KH x P2 

= P2 = 1.3 x 10-3 x 8.4

= 10.92 × 10-3

= 1.092 × 10-2 mol dm-3

∴ Solubility of O2 = 1.092 × 10-2 mol dm-3



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