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Solve the following :The solubility of dissolved oxygen to 27 °C is 2.6 × 10-3 mol dm-3 at 2 atm. Find its solubility at 8.4 atm and 27 °C. |
Answer» Given : Solubility of O2 = S1 = 2.6 × 10-3 mol dm-3 Initial pressure of O2 = P1 = 2 atm Final pressure of O2 = P2 = 8.4 atm Solubility of O2 = S2 = ? (i) By Henry’s law, S1 = KH x P1 ∴ Henry’s law constant KH is, KH = \(\frac{S_1}{P_1}\) = \(\frac{2.6 \times 10^{-3}}{2}\) = 1.3 × 10-3 mol dm-3 atm-1 (ii) Now, S2 = KH x P2 = P2 = 1.3 x 10-3 x 8.4 = 10.92 × 10-3 = 1.092 × 10-2 mol dm-3 ∴ Solubility of O2 = 1.092 × 10-2 mol dm-3 |
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